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-16x^2+86x-108=0
a = -16; b = 86; c = -108;
Δ = b2-4ac
Δ = 862-4·(-16)·(-108)
Δ = 484
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{484}=22$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(86)-22}{2*-16}=\frac{-108}{-32} =3+3/8 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(86)+22}{2*-16}=\frac{-64}{-32} =+2 $
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